What are the solutions to the equation solvefor v,K= 1/2 mv^2 ?

The solutions to the equation solvefor v,K= 1/2 mv^2 are v=sqrt((2K)/m),v=-sqrt((2K)/m);\quad m\ne 0

Find the zeros of solvefor v,K= 1/2 mv^2

The zeros of solvefor v,K= 1/2 mv^2 are v=sqrt((2K)/m),v=-sqrt((2K)/m);\quad m\ne 0

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solve for

v, K = \frac{1}{2} m v^{2}

v = \frac{2 K}{m}, v = - \frac{2 K}{m}; m \neq = 0

Solution steps

K = \frac{1}{2} m v^{2}

Switch sides

\frac{1}{2} m v^{2} = K

Multiply both sides by

2

m v^{2} = 2 K

Divide both sides by

m; m \neq = 0

v^{2} = \frac{2 K}{m}; m \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = \frac{2 K}{m}, v = - \frac{2 K}{m}; m \neq = 0

f (x) = x^{5} + 2 x + 1

f (x) = 3 x - 12

f (x) = - 2^{- x}

f (x) = - (x - 5)^{2} + 4

y = \frac{1}{2 x ^{2}} + \frac{x ^{4}}{16}

What are the solutions to the equation solvefor v,K= 1/2 mv^2 ?
The solutions to the equation solvefor v,K= 1/2 mv^2 are v=sqrt((2K)/m),v=-sqrt((2K)/m);\quad m\ne 0
Find the zeros of solvefor v,K= 1/2 mv^2
The zeros of solvefor v,K= 1/2 mv^2 are v=sqrt((2K)/m),v=-sqrt((2K)/m);\quad m\ne 0