What is the inverse of f(x)=7x^2-8 ?

The inverse of f(x)=7x^2-8 is sqrt((x+8)/7),-sqrt((x+8)/7)

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inverse of f(x)=7x^2-8

inverse

f (x) = 7 x^{2} - 8

\frac{x + 8}{7}, - \frac{x + 8}{7}

Solution steps

y = 7 x^{2} - 8

Replace

x

with

y

x = 7 y^{2} - 8

Solve for

y, x = 7 y^{2} - 8

\frac{x + 8}{7}, - \frac{x + 8}{7}

20 x - 40 y = 160

y = - \frac{3}{4} x - 6

- - x^{2} - 4 x + 5 + 3

\frac{1}{x - 9}

f (x) = x^{3} + 2 x^{2} + x - 7

What is the inverse of f(x)=7x^2-8 ?
The inverse of f(x)=7x^2-8 is sqrt((x+8)/7),-sqrt((x+8)/7)