What is the f(x)=sec^4(x)+sec^2(x)tan^2(x)-2tan^4(x) ?

The f(x)=sec^4(x)+sec^2(x)tan^2(x)-2tan^4(x) is

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f(x)=sec^4(x)+sec^2(x)tan^2(x)-2tan^4(x)

f (x) = sec^{4} (x) + sec^{2} (x) tan^{2} (x) - 2 tan^{4} (x)

Period : π

Domain : πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

Y Intercepts : (0, 1)

Asymptotes : None

Extreme Points : Minimum (πn, 1)

Interval Notation

Domain : [πn, \frac{π}{2} + πn) \cup (\frac{π}{2} + πn, π + πn)

Solution steps

Periodicity of

sec^{4} (x) + sec^{2} (x) tan^{2} (x) - 2 tan^{4} (x) : π

Domain of

sec^{4} (x) + sec^{2} (x) tan^{2} (x) - 2 tan^{4} (x) : πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

Axis interception points of

sec^{4} (x) + sec^{2} (x) tan^{2} (x) - 2 tan^{4} (x) :

Y Intercepts

: (0, 1)

Asymptotes of

sec^{4} (x) + sec^{2} (x) tan^{2} (x) - 2 tan^{4} (x) :

None

Extreme Points of

sec^{4} (x) + sec^{2} (x) tan^{2} (x) - 2 tan^{4} (x) :

Minimum

(πn, 1)

y = - 4 ∣ x ∣

y = tan (4 x)

y = x^{2} - 8 x + 10

f (x) = - 2 x^{2} - 4 x + 6

f (x) = - 2 x^{2} - 4 x + 1

What is the f(x)=sec^4(x)+sec^2(x)tan^2(x)-2tan^4(x) ?
The f(x)=sec^4(x)+sec^2(x)tan^2(x)-2tan^4(x) is