What is the domain of f(x)=sqrt(9-x^2)+sqrt(x+1) ?

The domain of f(x)=sqrt(9-x^2)+sqrt(x+1) is -1<= x<= 3

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domain of f(x)=sqrt(9-x^2)+sqrt(x+1)

domain

f (x) = 9 - x^{2} + x + 1

- 1 \leq x \leq 3

Interval Notation

[- 1, 3]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 3

The function domain

- 1 \leq x \leq 3

y^{2} = 2 x^{4} - 4

(x + 2)^{2}

x - 3

y = 3 x + 1

\frac{- 6 x + 71}{7 x - 46}

What is the domain of f(x)=sqrt(9-x^2)+sqrt(x+1) ?
The domain of f(x)=sqrt(9-x^2)+sqrt(x+1) is -1<= x<= 3