What is the domain of ((x+1))/(x^2-4) ?

The domain of ((x+1))/(x^2-4) is x 2

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domain of ((x+1))/(x^2-4)

domain

\frac{( x + 1 )}{x ^{2} - 4}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

f (x) = \frac{5 - x}{3 + 2 x}

f (x) = 3 x^{2} + 5 x - 2

y = \frac{1}{4} x + 7

sin (x)

f (x) = 4 x^{2} + 23 x - 6

What is the domain of ((x+1))/(x^2-4) ?
The domain of ((x+1))/(x^2-4) is x<-2\lor-2<x<2\lor x>2