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Popular >

p(x)=(x^2-16)(x^2-9)

Solution

p (x) = (x^{2} - 16) (x^{2} - 9)

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq - \frac{49}{4}

X Intercepts : (- 4, 0), (4, 0), (- 3, 0), (3, 0), Y Intercepts : (0, 144)

Asymptotes : None

Extreme Points : Minimum (- \frac{5}{2}, - \frac{49}{4}), Maximum (0, 144), Minimum (\frac{5}{2}, - \frac{49}{4})

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- \frac{49}{4}, \infty)

Solution steps

Domain of

(x^{2} - 16) (x^{2} - 9) : - \infty < x < \infty

Range of

(x^{2} - 16) (x^{2} - 9) : f (x) \geq - \frac{49}{4}

Axis interception points of

(x^{2} - 16) (x^{2} - 9) :

X Intercepts

: (- 4, 0), (4, 0), (- 3, 0), (3, 0),

Y Intercepts

: (0, 144)

Asymptotes of

(x^{2} - 16) (x^{2} - 9) :

None

Extreme Points of

(x^{2} - 16) (x^{2} - 9) :

Minimum

(- \frac{5}{2}, - \frac{49}{4}),

Maximum

(0, 144),

Minimum

(\frac{5}{2}, - \frac{49}{4})

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Frequently Asked Questions (FAQ)

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