What is the range of f(x)=(x+1)/(x-1) ?

The range of f(x)=(x+1)/(x-1) is f(x) 1

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range of f(x)=(x+1)/(x-1)

range

f (x) = \frac{x + 1}{x - 1}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x + 1}{x - 1}

Inverse of

\frac{x + 1}{x - 1} : \frac{1 + x}{x - 1}

\frac{1 + x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{1 + x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

(- 1, 5), (- 5, 5)

f (x) = \frac{5}{2 x ^{2} + 1}

(5, - 4), (- 1, - 4)

\frac{x ^{3}}{x + 2}

f (z) = 4 - z^{2}

What is the range of f(x)=(x+1)/(x-1) ?
The range of f(x)=(x+1)/(x-1) is f(x)<1\lor f(x)>1