What is the domain of f(x)=(x-1)/(x^2-4x+3) ?

The domain of f(x)=(x-1)/(x^2-4x+3) is x 3

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domain of f(x)=(x-1)/(x^2-4x+3)

domain

f (x) = \frac{x - 1}{x ^{2} - 4 x + 3}

x < 1 or 1 < x < 3 or x > 3

Interval Notation

(- \infty, 1) \cup (1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 1

The function domain

x < 1 or 1 < x < 3 or x > 3

f (x) = (x + 3)^{3} - 1

m = - \frac{7}{16}

(x^{2} - 9)^{6}

x^{4}

f (x) = 2 x^{3} - 24 x - 6

What is the domain of f(x)=(x-1)/(x^2-4x+3) ?
The domain of f(x)=(x-1)/(x^2-4x+3) is x<1\lor 1<x<3\lor x>3