What is the domain of f(x)=ln(x+1)+e^{x^2-3}+(x^2-4)^{5/3} ?

The domain of f(x)=ln(x+1)+e^{x^2-3}+(x^2-4)^{5/3} is x>-1

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domain of f(x)=ln(x+1)+e^{x^2-3}+(x^2-4)^{5/3}

domain

f (x) = ln (x + 1) + e^{x^{2} - 3} + (x^{2} - 4)^{\frac{5}{3}}

x > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find positive values for logs:

x > - 1

The function domain

x > - 1

f (θ) = cot (3 θ)

y = lo g_{\frac{2}{5}} (x)

f (x) = 3 x^{5} + ln (x) + 4 x^{3}

f (x) = x - 2 arctan (x)

y = e^{- l n (x)}

What is the domain of f(x)=ln(x+1)+e^{x^2-3}+(x^2-4)^{5/3} ?
The domain of f(x)=ln(x+1)+e^{x^2-3}+(x^2-4)^{5/3} is x>-1