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Popular >

distance (3,-4),(5,1)

Solution

distance

(3, - 4), (5, 1)

Solution

29

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(3, - 4)

and

(5, 1)

is

= (5 - 3)^{2} + (1 - (- 4))^{2}

Simplify

= 29

Popular Examples

periodicity of f(x)=-cos((6x)/7)periodicity

f (x) = - cos (\frac{6 x}{7})

domain of y=(3x)/(x^2-36)domain

y = \frac{3 x}{x ^{2} - 36}

range of (x-1)/(x^2-1)range

\frac{x - 1}{x ^{2} - 1}

inverse of f(x)=\sqrt[3]{x}inverse

symmetry y=x^2-4x+3 symmetry

y = x^{2} - 4 x + 3

Frequently Asked Questions (FAQ)

What is the distance (3,-4),(5,1) ?
The distance (3,-4),(5,1) is square root of 29