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Popular >

midpoint (1,-1),(5,3)

Solution

midpoint

(1, - 1), (5, 3)

Solution

(3, 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (1, - 1), (x_{2}, y_{2}) = (5, 3)

= (\frac{5 + 1}{2}, \frac{3 - 1}{2})

Refine

= (3, 1)

Popular Examples

line m=-1,(-5,1)line

m = - 1, (- 5, 1)

inverse of f(x)=x^2+4,x>= 0 inverse

f (x) = x^{2} + 4, x \geq 0

range of f(x)=((6x^2-5))/((2x^2+6))range

f (x) = \frac{( 6 x ^{2} - 5 )}{( 2 x ^{2} + 6 )}

domain of ((1))/((-10(\frac{(1)){(-5x-6)})+3)}domain

\frac{( 1 )}{( - 10 ( \frac{( 1 )}{( - 5 x - 6 )} ) + 3 )}

inverse of 3x^2 inverse

3 x^{2}

Frequently Asked Questions (FAQ)

What is the midpoint (1,-1),(5,3) ?
The midpoint (1,-1),(5,3) is (3,1)