What is the critical f(x)=6x^3-9x^2-36x ?

The critical f(x)=6x^3-9x^2-36x is x=-1,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=6x^3-9x^2-36x

critical points

f (x) = 6 x^{3} - 9 x^{2} - 36 x

x = - 1, x = 2

Solution steps

6 x^{3} - 9 x^{2} - 36 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 2

Identify critical points not in

f (x)

domain

Domain of

6 x^{3} - 9 x^{2} - 36 x : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 2

f (x) = 8 t^{\frac{2}{3}} + t^{\frac{5}{3}}

f (x) = 1 - 4 x^{2}

5 (\frac{1}{4})^{x}

(- 2, - 5), (- 4, - 2)

f (x) = x^{4}

What is the critical f(x)=6x^3-9x^2-36x ?
The critical f(x)=6x^3-9x^2-36x is x=-1,x=2