What is the domain of 1+(8+x)^{1/2} ?

The domain of 1+(8+x)^{1/2} is x>=-8

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domain of 1+(8+x)^{1/2}

domain

1 + (8 + x)^{\frac{1}{2}}

x \geq - 8

Interval Notation

[- 8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

The function domain

x \geq - 8

f (x) = 4 x^{3} - 6 x^{2} + 5 x - 2

\frac{3}{x - 5}

\frac{8}{x ^{2} - 81}

f (x) = x^{\frac{1}{7}} (x + 8)

f (x) = \frac{5}{x - 7}