What is the domain of f(x)=sqrt(x^2-x) ?

The domain of f(x)=sqrt(x^2-x) is x = 1

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domain of f(x)=sqrt(x^2-x)

domain

f (x) = x^{2} - x

x \leq 0 or x \geq 1

Interval Notation

(- \infty, 0] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 1

The function domain

x \leq 0 or x \geq 1

y = x - 3

y = \frac{x + 2}{x + 4}

y = 16 - x^{2}

sin (\frac{2 π}{3} (x + 2))

y = x^{2} - x

What is the domain of f(x)=sqrt(x^2-x) ?
The domain of f(x)=sqrt(x^2-x) is x<= 0\lor x>= 1