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Popular >

36y^2=(x^2-4)^3,2<= x<= 3,y>= 0

Solution

36 y^{2} = (x^{2} - 4)^{3}, 2 \leq x \leq 3, y \geq 0

Solution

Domain : 2 \leq x \leq 3

Range : 0 \leq f (y) \leq 125

X Intercepts : (2, 0)

Asymptotes : None

Extreme Points : Minimum (2, 0), Maximum (3, 125)

+1

Interval Notation

Domain : [2, 3]

Range : [0, 125]

Solution steps

Domain of

(x^{2} - 4)^{3}, 2 \leq x \leq 3 : 2 \leq x \leq 3

Range of

(x^{2} - 4)^{3}, 2 \leq x \leq 3 : 0 \leq f (y) \leq 125

Axis interception points of

(x^{2} - 4)^{3}, 2 \leq x \leq 3 :

X Intercepts

: (2, 0)

Asymptotes of

(x^{2} - 4)^{3}, 2 \leq x \leq 3 :

None

Extreme Points of

(x^{2} - 4)^{3}, 2 \leq x \leq 3 :

Minimum

(2, 0),

Maximum

(3, 125)

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f(x)= 8/(x^2-4)

f (x) = \frac{8}{x ^{2} - 4}

f (t) = e^{4 t} + 5

f (x) = 5 x

Frequently Asked Questions (FAQ)

What is the 36y^2=(x^2-4)^3,2<= x<= 3,y>= 0 ?
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