What is the range of sqrt(x^2-25) ?

The range of sqrt(x^2-25) is f(x)>= 0

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range of sqrt(x^2-25)

range

x^{2} - 25

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

x^{2} - 25 : x \leq - 5 or x \geq 5

Extreme Points of

x^{2} - 25 :

Minimum

(- 5, 0),

Minimum

(5, 0)

Find the range for the interval

- \infty < x \leq - 5 : 0 \leq f (x) < \infty

Find the range for the interval

5 \leq x < \infty : 0 \leq f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) \geq 0 or f (x) \geq 0

f (x) \geq 0

\frac{7 x - 2}{3}

y = - 2 x + 7

\frac{5 x - 2}{7 x + 3}

f (x) = - x + 3

f (x) = \frac{x - 3}{x - 7}