What is the domain of f(x)= 9/(sqrt(x-4)) ?

The domain of f(x)= 9/(sqrt(x-4)) is x>4

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domain of f(x)= 9/(sqrt(x-4))

domain

f (x) = \frac{9}{x - 4}

x > 4

Interval Notation

(4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

x > 4

f (x) = \frac{x ^{2}}{x ^{2} + 3}

f (x) = x - 1 + 2 y = 2

f (x) = \frac{5 x ^{3} - 8}{4 x ^{2} + 5 x}

f (x) = \frac{1}{3} e^{2 x} - 1

f (x) = 7 + (4 + x)^{\frac{1}{2}}

What is the domain of f(x)= 9/(sqrt(x-4)) ?
The domain of f(x)= 9/(sqrt(x-4)) is x>4