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Popular >

h(x)=(x-2)(2x+3)

Solution

h (x) = (x - 2) (2 x + 3)

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq - \frac{49}{8}

X Intercepts : (2, 0), (- \frac{3}{2}, 0), Y Intercepts : (0, - 6)

Vertex : Minimum (\frac{1}{4}, - \frac{49}{8})

Inverse : \frac{1 + 8 x + 49}{4}, \frac{1 - 8 x + 49}{4}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- \frac{49}{8}, \infty)

Solution steps

Domain of

(x - 2) (2 x + 3) : - \infty < x < \infty

Range of

(x - 2) (2 x + 3) : f (x) \geq - \frac{49}{8}

Axis interception points of

(x - 2) (2 x + 3) :

X Intercepts

: (2, 0), (- \frac{3}{2}, 0),

Y Intercepts

: (0, - 6)

Vertex of

(x - 2) (2 x + 3) :

Minimum

(\frac{1}{4}, - \frac{49}{8})

Inverse of

(x - 2) (2 x + 3) : \frac{1 + 8 x + 49}{4}, \frac{1 - 8 x + 49}{4}

Popular Examples

f (t) = t^{3} e^{2 t}

f (y) = y^{\frac{2}{5}}

y= x/(sqrt(x+1))

y = \frac{x}{x + 1}

f(x)=(x+2)/(x^2+x-2)

f (x) = \frac{x + 2}{x ^{2} + x - 2}

y = - (x - 2)^{2} + 4

Frequently Asked Questions (FAQ)

What is the h(x)=(x-2)(2x+3) ?
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