What is the asymptotes of y= 1/((x-9)(x+3)) ?

The asymptotes of y= 1/((x-9)(x+3)) is Vertical: x=-3,x=9,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of y= 1/((x-9)(x+3))

asymptotes

y = \frac{1}{( x - 9 ) ( x + 3 )}

Vertical : x = - 3, x = 9, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{( x - 9 ) ( x + 3 )} : x = - 3, x = 9

Horizontal Asymptotes of

\frac{1}{( x - 9 ) ( x + 3 )} : y = 0

Slant Asymptotes of

\frac{1}{( x - 9 ) ( x + 3 )} :

None

Vertical : x = - 3, x = 9, Horizontal : y = 0

f (x) = \frac{x}{x ( x + 5 )}

f (x) = \frac{1}{x ^{2} + 7}

f (x) = 0.5 x^{2} - 8 x + 35

f (x) = - x^{4} - 7 x^{3} + 3 x + 8

5 - x + 1

What is the asymptotes of y= 1/((x-9)(x+3)) ?
The asymptotes of y= 1/((x-9)(x+3)) is Vertical: x=-3,x=9,Horizontal: y=0