What is the p(x)=(-2x^5+x^4+5x^3+4x+1)/((x-2)) ?

The p(x)=(-2x^5+x^4+5x^3+4x+1)/((x-2)) is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

p(x)=(-2x^5+x^4+5x^3+4x+1)/((x-2))

p (x) = \frac{- 2 x ^{5} + x ^{4} + 5 x ^{3} + 4 x + 1}{( x - 2 )}

Domain : x < 2 or x > 2

X Intercepts : (- 0.23491 \dots, 0), (2.01523 \dots, 0), (- 1.55468 \dots, 0), Y Intercepts : (0, - \frac{1}{2})

Asymptotes : Vertical x = 2

Extreme Points : Maximum (- 1.11266 \dots, 1.73315 \dots)

Interval Notation

Domain : (- \infty, 2) \cup (2, \infty)

Solution steps

Domain of

\frac{- 2 x ^{5} + x ^{4} + 5 x ^{3} + 4 x + 1}{x - 2} : x < 2 or x > 2

Axis interception points of

\frac{- 2 x ^{5} + x ^{4} + 5 x ^{3} + 4 x + 1}{x - 2} :

X Intercepts

: (- 0.23491 \dots, 0), (2.01523 \dots, 0), (- 1.55468 \dots, 0),

Y Intercepts

: (0, - \frac{1}{2})

Asymptotes of

\frac{- 2 x ^{5} + x ^{4} + 5 x ^{3} + 4 x + 1}{x - 2} :

Vertical

: x = 2

Extreme Points of

\frac{- 2 x ^{5} + x ^{4} + 5 x ^{3} + 4 x + 1}{x - 2} :

Maximum

(- 1.11266 \dots, 1.73315 \dots)

f (x) = (1 + ln (x))^{1 + l n (x)}

y = x cos (2 x) - e^{x} sin (x)

f (x) = \frac{x + 6}{2 x - 4}

f (x) = ln (\frac{3 x - 1}{x + 2})

f (x) = \frac{x + 1}{2 x}

What is the p(x)=(-2x^5+x^4+5x^3+4x+1)/((x-2)) ?
The p(x)=(-2x^5+x^4+5x^3+4x+1)/((x-2)) is