What is the f(x)=\sqrt[5]{2x-12}+2/(sqrt(x-3)) ?

The f(x)=\sqrt[5]{2x-12}+2/(sqrt(x-3)) is

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f(x)=\sqrt[5]{2x-12}+2/(sqrt(x-3))

Domain : x > 3

Intercepts : None

Asymptotes : Vertical x = 3

Interval Notation

Domain : (3, \infty)

Solution steps

Domain of

Range of

Axis interception points of

None

Asymptotes of

Vertical

: x = 3

Extreme Points of

Minimum

y = - 2 x^{2} + 16 x - 24

f (x) = \frac{8}{x - 7}

f (x) = - 4 cos (x)

f (c) = cos (ec)

f (x) = (x - 4)^{2} - 4

What is the f(x)=\sqrt[5]{2x-12}+2/(sqrt(x-3)) ?
The f(x)=\sqrt[5]{2x-12}+2/(sqrt(x-3)) is