What is the inverse of sqrt((x-3)/(x-1)) ?

The inverse of sqrt((x-3)/(x-1)) is (-3+x^2)/(x^2-1)

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inverse of sqrt((x-3)/(x-1))

inverse

\frac{x - 3}{x - 1}

\frac{- 3 + x ^{2}}{x ^{2} - 1}

Solution steps

y = \frac{x - 3}{x - 1}

Replace

x

with

y

x = \frac{y - 3}{y - 1}

Solve for

y, x = \frac{y - 3}{y - 1}

\frac{- 3 + x ^{2}}{x ^{2} - 1}

f (x) = \frac{x + 2}{x ^{6} - 64}

(\frac{3}{2}, \frac{4}{3}), (3, - 2)

f (x) = x^{2} + 1

(8, 4), (4, 2)

(0, 4), (7, 8)

What is the inverse of sqrt((x-3)/(x-1)) ?
The inverse of sqrt((x-3)/(x-1)) is (-3+x^2)/(x^2-1)