What is the domain of f(x)=ln(x-1)+e^{(x^2-3)}+(x^2-4)^{(5/3)} ?

The domain of f(x)=ln(x-1)+e^{(x^2-3)}+(x^2-4)^{(5/3)} is x>1

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domain of f(x)=ln(x-1)+e^{(x^2-3)}+(x^2-4)^{(5/3)}

domain

f (x) = ln (x - 1) + e^{(x^{2} - 3)} + (x^{2} - 4)^{(\frac{5}{3})}

x > 1

Interval Notation

(1, \infty)

Solution steps

Find positive values for logs:

x > 1

The function domain

x > 1

y = x^{2} - 4

y = - 2 x^{2} - 24 x - 88

g (x) = \frac{1}{x + 2}

f (x) = lo g_{10} (3) x^{4}

y = lo g_{x} (x + 3)

What is the domain of f(x)=ln(x-1)+e^{(x^2-3)}+(x^2-4)^{(5/3)} ?
The domain of f(x)=ln(x-1)+e^{(x^2-3)}+(x^2-4)^{(5/3)} is x>1