What is the domain of f(y)=ln(y-1)+e^{y^2-3}+(y^2-4)^{5/3} ?

The domain of f(y)=ln(y-1)+e^{y^2-3}+(y^2-4)^{5/3} is y>1

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domain of f(y)=ln(y-1)+e^{y^2-3}+(y^2-4)^{5/3}

domain

f (y) = ln (y - 1) + e^{y^{2} - 3} + (y^{2} - 4)^{\frac{5}{3}}

y > 1

Interval Notation

(1, \infty)

Solution steps

Find positive values for logs:

y > 1

The function domain

y > 1

y = x^{2} + 6 x + 12

y = x^{2} + 6 x - 16

f (t) = 6 t^{3} + 2 cos (9 t)

f (x) = - \frac{1}{x ^{3}}

f (x) = 10 - 2 x

What is the domain of f(y)=ln(y-1)+e^{y^2-3}+(y^2-4)^{5/3} ?
The domain of f(y)=ln(y-1)+e^{y^2-3}+(y^2-4)^{5/3} is y>1