What is the domain of y=(ln(x^2-4))/(2x^2+x-15) ?

The domain of y=(ln(x^2-4))/(2x^2+x-15) is x 5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(ln(x^2-4))/(2x^2+x-15)

domain

y = \frac{ln ( x ^{2} - 4 )}{2 x ^{2} + x - 15}

x < - 3 or - 3 < x < - 2 or 2 < x < \frac{5}{2} or x > \frac{5}{2}

Interval Notation

(- \infty, - 3) \cup (- 3, - 2) \cup (2, \frac{5}{2}) \cup (\frac{5}{2}, \infty)

Solution steps

Find positive values for logs:

x < - 2 or x > 2

Find undefined (singularity) points:

x = \frac{5}{2}, x = - 3

Combine real regions and undefined points for final function domain

x < - 3 or - 3 < x < - 2 or 2 < x < \frac{5}{2} or x > \frac{5}{2}

f (x) = 13 x - 9

y = 5 x - 5

f (x) = sin (π + 6 x)

\frac{x - 6}{x ^{2} - x - 12}

f (x) = \frac{- 6 x + 8}{8 x - 3}

What is the domain of y=(ln(x^2-4))/(2x^2+x-15) ?
The domain of y=(ln(x^2-4))/(2x^2+x-15) is x<-3\lor-3<x<-2\lor 2<x< 5/2 \lor x> 5/2