What is the perpendicular y= 1/5 x+5,(8,-3) ?

The perpendicular y= 1/5 x+5,(8,-3) is y=-5x+37

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perpendicular y= 1/5 x+5,(8,-3)

perpendicular

y = \frac{1}{5} x + 5, (8, - 3)

y = - 5 x + 37

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{1}{5} x + 5

that passes through

(8, - 3)

Find the slope of

y = \frac{1}{5} x + 5 : m = \frac{1}{5}

Compute the slope of the perpendicular line:

m_{p} = - 5

Find the line with slope m=

- 5

and passing through

(8, - 3) : y = - 5 x + 37

y = - 5 x + 37

f (x) = 2 x + 12

f (x) = - \frac{4}{5} x + 2

f (x) = 9 - 3 x^{2}

f (x) = \frac{( x + 11 )}{x - 10}

f (x) = lo g_{2} (x - 6)

What is the perpendicular y= 1/5 x+5,(8,-3) ?
The perpendicular y= 1/5 x+5,(8,-3) is y=-5x+37