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Popular >

h(t)=40t-16t^2

Solution

h (t) = 40 t - 16 t^{2}

Solution

Domain : - \infty < t < \infty

Range : f (t) \leq 25

X Intercepts : (0, 0), (\frac{5}{2}, 0), Y Intercepts : (0, 0)

Vertex : Maximum (\frac{5}{4}, 25)

Inverse : - \frac{- 5 + - t + 25}{4}, \frac{- t + 25 + 5}{4}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, 25]

Solution steps

Domain of

40 t - 16 t^{2} : - \infty < t < \infty

Range of

40 t - 16 t^{2} : f (t) \leq 25

Axis interception points of

40 t - 16 t^{2} :

X Intercepts

: (0, 0), (\frac{5}{2}, 0),

Y Intercepts

: (0, 0)

Vertex of

40 t - 16 t^{2} :

Maximum

(\frac{5}{4}, 25)

Inverse of

40 t - 16 t^{2} : - \frac{- 5 + - t + 25}{4}, \frac{- t + 25 + 5}{4}

Popular Examples

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f (x) = 2 x^{3} - 3 x^{2} - 12 x + 3

y = 9 x - 3

y = x^{2} + 6 x - 5

f(x)=x^4+2x^3-5x^2-x+6

f (x) = x^{4} + 2 x^{3} - 5 x^{2} - x + 6

f (t) = sin (2 π t)

Frequently Asked Questions (FAQ)

What is the h(t)=40t-16t^2 ?
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