What is the f(x)=2700sqrt(x)+900,0<= x<= 5 ?

The f(x)=2700sqrt(x)+900,0<= x<= 5 is

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f(x)=2700sqrt(x)+900,0<= x<= 5

f (x) = 2700 x + 900, 0 \leq x \leq 5

Domain : 0 \leq x \leq 5

Range : 900 \leq f (x) \leq 27005 + 900

Y Intercepts : (0, 900)

Asymptotes : None

Extreme Points : Minimum (0, 900), Maximum (5, 27005 + 900)

Interval Notation

Domain : [0, 5]

Range : [900, 27005 + 900]

Solution steps

Domain of

2700 x + 900, 0 \leq x \leq 5 : 0 \leq x \leq 5

Range of

2700 x + 900, 0 \leq x \leq 5 : 900 \leq f (x) \leq 27005 + 900

Axis interception points of

2700 x + 900, 0 \leq x \leq 5 :

Y Intercepts

: (0, 900)

Asymptotes of

2700 x + 900, 0 \leq x \leq 5 :

None

Extreme Points of

2700 x + 900, 0 \leq x \leq 5 :

Minimum

(0, 900),

Maximum

(5, 27005 + 900)

f (x) = (1 - cos (x)) sin (x)

f (x) = ∣ x + 8 ∣

y = x x + 3

f (t) = sinh (t) cos (2 t)

f (x) = arcsin^{2} (x)

What is the f(x)=2700sqrt(x)+900,0<= x<= 5 ?
The f(x)=2700sqrt(x)+900,0<= x<= 5 is