What is the f(n)=(4^{n-1}+1)/(4^{1-n)+1} ?

The f(n)=(4^{n-1}+1)/(4^{1-n)+1} is

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f(n)=(4^{n-1}+1)/(4^{1-n)+1}

f (n) = \frac{4 ^{n - 1} + 1}{4 ^{1 - n} + 1}

Domain : - \infty < n < \infty

Range : f (x) > 0

Y Intercepts : (0, \frac{1}{4})

Asymptotes : Horizontal y = 0

Extreme Points : None

Interval Notation

Domain : (- \infty, \infty)

Range : (0, \infty)

Solution steps

Domain of

\frac{4 ^{n - 1} + 1}{4 ^{1 - n} + 1} : - \infty < n < \infty

Range of

\frac{4 ^{n - 1} + 1}{4 ^{1 - n} + 1} : f (x) > 0

Axis interception points of

\frac{4 ^{n - 1} + 1}{4 ^{1 - n} + 1} :

Y Intercepts

: (0, \frac{1}{4})

Asymptotes of

\frac{4 ^{n - 1} + 1}{4 ^{1 - n} + 1} :

Horizontal

: y = 0

Extreme Points of

\frac{4 ^{n - 1} + 1}{4 ^{1 - n} + 1} :

None

f (x) = 2 sin^{2} (x) + sin (x)

f (x) = \frac{( x ^{3} - x + 42 )}{( x - 7 )}

f (x) = \frac{3 x - 5}{2 x + 1}

f (x) = \frac{2 x - 3}{2 x - 3}

y = x^{3} - 6 x^{2} + 12 x - 8