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Popular >

midpoint (4,14),(16,4)

Solution

midpoint

(4, 14), (16, 4)

Solution

(10, 9)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (4, 14), (x_{2}, y_{2}) = (16, 4)

= (\frac{16 + 4}{2}, \frac{4 + 14}{2})

Refine

= (10, 9)

Popular Examples

asymptotes of sqrt(4-x^2)asymptotes

4 - x^{2}

asymptotes of f(x)=(x^4-256)/(2x^2-8x)asymptotes

f (x) = \frac{x ^{4} - 256}{2 x ^{2} - 8 x}

midpoint (-2,1),(4,-3)midpoint

(- 2, 1), (4, - 3)

asymptotes of f(x)=(4x)/(x^2-25)asymptotes

f (x) = \frac{4 x}{x ^{2} - 25}

f (x) = - 3 x

Frequently Asked Questions (FAQ)

What is the midpoint (4,14),(16,4) ?
The midpoint (4,14),(16,4) is (10,9)