What is the f(x)=sqrt(14-x)-4,-2<= x<= 5 ?

The f(x)=sqrt(14-x)-4,-2<= x<= 5 is

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f(x)=sqrt(14-x)-4,-2<= x<= 5

f (x) = 14 - x - 4, - 2 \leq x \leq 5

Domain : - 2 \leq x \leq 5

Range : - 1 \leq f (x) \leq 0

X Intercepts : (- 2, 0), Y Intercepts : (0, 14 - 4)

Asymptotes : None

Extreme Points : Maximum (- 2, 0), Minimum (5, - 1)

Interval Notation

Domain : [- 2, 5]

Range : [- 1, 0]

Solution steps

Domain of

14 - x - 4, - 2 \leq x \leq 5 : - 2 \leq x \leq 5

Range of

14 - x - 4, - 2 \leq x \leq 5 : - 1 \leq f (x) \leq 0

Axis interception points of

14 - x - 4, - 2 \leq x \leq 5 :

X Intercepts

: (- 2, 0),

Y Intercepts

: (0, 14 - 4)

Asymptotes of

14 - x - 4, - 2 \leq x \leq 5 :

None

Extreme Points of

14 - x - 4, - 2 \leq x \leq 5 :

Maximum

(- 2, 0),

Minimum

(5, - 1)

f (x) = 2 - e^{x - 3}

f (x) = \frac{2 x + 10}{5 x - 25}

f (x) = - x^{2} + 8 x - 13

f (x) = {x^{2} - 2 : x \geq 1, \frac{1}{x - 7} : x < 1}

y = 5 sin (2 x)