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Popular >

h(x)=-2x^2+4x+16

Solution

h (x) = - 2 x^{2} + 4 x + 16

Solution

Domain : - \infty < x < \infty

Range : f (x) \leq 18

X Intercepts : (- 2, 0), (4, 0), Y Intercepts : (0, 16)

Vertex : Maximum (1, 18)

Inverse : - \frac{- 4 + - 8 x + 144}{4}, - \frac{- 4 - - 8 x + 144}{4}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, 18]

Solution steps

Domain of

- 2 x^{2} + 4 x + 16 : - \infty < x < \infty

Range of

- 2 x^{2} + 4 x + 16 : f (x) \leq 18

Axis interception points of

- 2 x^{2} + 4 x + 16 :

X Intercepts

: (- 2, 0), (4, 0),

Y Intercepts

: (0, 16)

Vertex of

- 2 x^{2} + 4 x + 16 :

Maximum

(1, 18)

Inverse of

- 2 x^{2} + 4 x + 16 : - \frac{- 4 + - 8 x + 144}{4}, - \frac{- 4 - - 8 x + 144}{4}

Popular Examples

f (x) = 24

f(x)=2+sqrt(16+x^2)

f (x) = 2 + 16 + x^{2}

y = - 2 x^{2} + 3 x - 1

f (x) = x^{2} - 5 x + 24

y = 2 x^{2} - 12 x + 18

Frequently Asked Questions (FAQ)

What is the h(x)=-2x^2+4x+16 ?
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