What is the f(x)=(x^3-3x^2-4x+12)/(x^2-x-6) ?

The f(x)=(x^3-3x^2-4x+12)/(x^2-x-6) is

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f(x)=(x^3-3x^2-4x+12)/(x^2-x-6)

f (x) = \frac{x ^{3} - 3 x ^{2} - 4 x + 12}{x ^{2} - x - 6}

Domain : x < - 2 or - 2 < x < 3 or x > 3

Range : f (x) < - 4 or - 4 < f (x) < 1 or f (x) > 1

X Intercepts : (2, 0), Y Intercepts : (0, - 2)

Asymptotes : Slant y = x - 2

Extreme Points : None

Interval Notation

Domain : (- \infty, - 2) \cup (- 2, 3) \cup (3, \infty)

Range : (- \infty, - 4) \cup (- 4, 1) \cup (1, \infty)

Solution steps

Domain of

\frac{x ^{3} - 3 x ^{2} - 4 x + 12}{x ^{2} - x - 6} : x < - 2 or - 2 < x < 3 or x > 3

Range of

\frac{x ^{3} - 3 x ^{2} - 4 x + 12}{x ^{2} - x - 6} : f (x) < - 4 or - 4 < f (x) < 1 or f (x) > 1

Axis interception points of

\frac{x ^{3} - 3 x ^{2} - 4 x + 12}{x ^{2} - x - 6} :

X Intercepts

: (2, 0),

Y Intercepts

: (0, - 2)

Asymptotes of

\frac{x ^{3} - 3 x ^{2} - 4 x + 12}{x ^{2} - x - 6} :

Slant

: y = x - 2

Extreme Points of

\frac{x ^{3} - 3 x ^{2} - 4 x + 12}{x ^{2} - x - 6} :

None

g (x) = x + 1 - \frac{1}{x}

y = 7 x + 9

f (m) = m - 3

f (x) = \frac{x - 4}{- 4 x - 16}

y = - x^{2} + 3 x + 1

What is the f(x)=(x^3-3x^2-4x+12)/(x^2-x-6) ?
The f(x)=(x^3-3x^2-4x+12)/(x^2-x-6) is