What is the Q(x)=(2x^2-4x+2)/(2x^3-5+5x^2-2x) ?

The Q(x)=(2x^2-4x+2)/(2x^3-5+5x^2-2x) is

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Q(x)=(2x^2-4x+2)/(2x^3-5+5x^2-2x)

Q (x) = \frac{2 x ^{2} - 4 x + 2}{2 x ^{3} - 5 + 5 x ^{2} - 2 x}

Domain : x < - \frac{5}{2} or - \frac{5}{2} < x < - 1 or - 1 < x < 1 or x > 1

Range : f (x) < 0 or 0 < f (x) \leq \frac{2 ( 11 - 4 7 )}{9} or f (x) \geq \frac{2 ( 4 7 + 11 )}{9}

Y Intercepts : (0, - \frac{2}{5})

Asymptotes : Vertical x = - \frac{5}{2}, x = - 1, Horizontal y = 0

Extreme Points : Minimum (1 - 7, \frac{2 ( 11 + 4 7 )}{9}), Maximum (1 + 7, \frac{2 ( 11 - 4 7 )}{9})

Interval Notation

Domain : (- \infty, - \frac{5}{2}) \cup (- \frac{5}{2}, - 1) \cup (- 1, 1) \cup (1, \infty)

Range : (- \infty, 0) \cup (0, \frac{2 ( 11 - 4 7 )}{9}] \cup [\frac{2 ( 4 7 + 11 )}{9}, \infty)

Solution steps

Domain of

\frac{2 x ^{2} - 4 x + 2}{2 x ^{3} - 5 + 5 x ^{2} - 2 x} : x < - \frac{5}{2} or - \frac{5}{2} < x < - 1 or - 1 < x < 1 or x > 1

Range of

\frac{2 x ^{2} - 4 x + 2}{2 x ^{3} - 5 + 5 x ^{2} - 2 x} : f (x) < 0 or 0 < f (x) \leq \frac{2 ( 11 - 4 7 )}{9} or f (x) \geq \frac{2 ( 4 7 + 11 )}{9}

Axis interception points of

\frac{2 x ^{2} - 4 x + 2}{2 x ^{3} - 5 + 5 x ^{2} - 2 x} :

Y Intercepts

: (0, - \frac{2}{5})

Asymptotes of

\frac{2 x ^{2} - 4 x + 2}{2 x ^{3} - 5 + 5 x ^{2} - 2 x} :

Vertical

: x = - \frac{5}{2}, x = - 1,

Horizontal

: y = 0

Extreme Points of

\frac{2 x ^{2} - 4 x + 2}{2 x ^{3} - 5 + 5 x ^{2} - 2 x} :

Minimum

(1 - 7, \frac{2 ( 11 + 4 7 )}{9}),

Maximum

(1 + 7, \frac{2 ( 11 - 4 7 )}{9})

f (x) = x^{3} + x^{2} - 14 x - 24

f (x) = - x^{2} + 6 x + 1

y = \frac{2}{5} x + 1

f (x) = ∣ - x ∣

f (x) = 8 x^{3} + 30 x^{2} + 24 x + 10

What is the Q(x)=(2x^2-4x+2)/(2x^3-5+5x^2-2x) ?
The Q(x)=(2x^2-4x+2)/(2x^3-5+5x^2-2x) is