What is the derivative of x+sin(2x) ?

The derivative of x+sin(2x) is 1+cos(2x)*2

What is the first derivative of x+sin(2x) ?

The first derivative of x+sin(2x) is 1+cos(2x)*2

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\frac{d}{d x} (x + sin (2 x))

1 + cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (x + sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (sin (2 x))

\frac{d x}{d x} = 1

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= 1 + cos (2 x) \cdot 2

f (c) = \frac{1}{c ^{\frac{3}{5}}}

f (x) = cos (x) - cos (2 x)

f (x) = sin (8 x) cos (8 x)

f (x) = \frac{12}{x - 5}

f (x) = (x + 1) (x - 3)

What is the derivative of x+sin(2x) ?
The derivative of x+sin(2x) is 1+cos(2x)*2
What is the first derivative of x+sin(2x) ?
The first derivative of x+sin(2x) is 1+cos(2x)*2