What is the domain of f(x)=((2x^3+3x^2))/(x^3-4x) ?

The domain of f(x)=((2x^3+3x^2))/(x^3-4x) is x 2

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domain of f(x)=((2x^3+3x^2))/(x^3-4x)

domain

f (x) = \frac{( 2 x ^{3} + 3 x ^{2} )}{x ^{3} - 4 x}

x < - 2 or - 2 < x < 0 or 0 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 0) \cup (0, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 2, x = 2

The function domain

x < - 2 or - 2 < x < 0 or 0 < x < 2 or x > 2

f (x) = x^{2} + 2 x + 3

f (x) = \frac{x + 5}{x - 5}

f (x) = \frac{2 x + 3}{5 x - 2}

f (x) = \frac{6}{x ^{2} + 10 x + 25}

m = 6, (- 2, - 3)

What is the domain of f(x)=((2x^3+3x^2))/(x^3-4x) ?
The domain of f(x)=((2x^3+3x^2))/(x^3-4x) is x<-2\lor-2<x<0\lor 0<x<2\lor x>2