What is the domain of sqrt((x-6)/(2x^2-5x+3)) ?

The domain of sqrt((x-6)/(2x^2-5x+3)) is 1 = 6

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domain of sqrt((x-6)/(2x^2-5x+3))

domain

\frac{x - 6}{2 x ^{2} - 5 x + 3}

1 < x < \frac{3}{2} or x \geq 6

Interval Notation

(1, \frac{3}{2}) \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

1 < x < \frac{3}{2} or x \geq 6

Find undefined (singularity) points:

x = \frac{3}{2}, x = 1

Combine real regions and undefined points for final function domain

1 < x < \frac{3}{2} or x \geq 6

y = 6 x - 8

f (x) = \frac{x ^{4}}{x + 12}

f (x) = lo g_{3} (x - 9)

f (x) = \frac{x ^{3} - 9 x}{x + 2}

f (x) = \frac{π}{2} + sin (x)

What is the domain of sqrt((x-6)/(2x^2-5x+3)) ?
The domain of sqrt((x-6)/(2x^2-5x+3)) is 1<x< 3/2 \lor x>= 6