What is the domain of y=ln(sqrt(1-x^2)) ?

The domain of y=ln(sqrt(1-x^2)) is -1<x<1

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domain of y=ln(sqrt(1-x^2))

domain

y = ln (1 - x^{2})

- 1 < x < 1

Interval Notation

(- 1, 1)

Solution steps

Find positive values for logs:

- 1 < x < 1

The function domain

- 1 < x < 1

f (x) = \frac{2 x ^{3}}{3}

h (x) = x^{2} - 4

f (x) = (x^{2} - 1) (x^{2} - 10 x + \frac{2}{x ^{2}})

8 b + q b

f (x) = \frac{- 2}{x}

What is the domain of y=ln(sqrt(1-x^2)) ?
The domain of y=ln(sqrt(1-x^2)) is -1<x<1