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midpoint
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inverse of f(x)=4(x+1)asymptotes of (x^2-x-3)/(x+1)intercepts of (5x)/(x+3)intercepts of f(x)=(x-3)(x+2)(x-7)inverse of f(x)=2x+3y=6
Frequently Asked Questions (FAQ)
What is the midpoint (1,0),(1,-3) ?
The midpoint (1,0),(1,-3) is (1,-3/2)