What is the perpendicular y= 10/7 x-3,(5,-4) ?

The perpendicular y= 10/7 x-3,(5,-4) is y=-7/10 x-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular y= 10/7 x-3,(5,-4)

perpendicular

y = \frac{10}{7} x - 3, (5, - 4)

y = - \frac{7}{10} x - \frac{1}{2}

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{10}{7} x - 3

that passes through

(5, - 4)

Find the slope of

y = \frac{10}{7} x - 3 : m = \frac{10}{7}

Compute the slope of the perpendicular line:

m_{p} = - \frac{7}{10}

Find the line with slope m=

- \frac{7}{10}

and passing through

(5, - 4) : y = - \frac{7}{10} x - \frac{1}{2}

y = - \frac{7}{10} x - \frac{1}{2}

f (x) = (\frac{x ^{3} + 2}{x ^{2} - 9})

f (x) = \frac{1}{x ^{3}}

\frac{1}{1 - \frac{1}{x - 2}}

x^{4} - 4 x^{2}

f (x) = \frac{5 x + 2}{20 x ^{2} - 11 x - 3}

What is the perpendicular y= 10/7 x-3,(5,-4) ?
The perpendicular y= 10/7 x-3,(5,-4) is y=-7/10 x-1/2