What is the f(x)=(tan(x)-sin(x))/(1-sec(x)) ?

The f(x)=(tan(x)-sin(x))/(1-sec(x)) is

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f(x)=(tan(x)-sin(x))/(1-sec(x))

f (x) = \frac{tan ( x ) - sin ( x )}{1 - sec ( x )}

Period : 2 π

Domain : 2 πn < x < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < x < \frac{3 π}{2} + 2 πn or \frac{3 π}{2} + 2 πn < x < 2 π + 2 πn

Range : - 1 < f (x) < 1

X Intercepts : (π + 2 πn, 0)

Asymptotes : None

Extreme Points : None

Interval Notation

Domain : (2 πn, \frac{π}{2} + 2 πn) \cup (\frac{π}{2} + 2 πn, \frac{3 π}{2} + 2 πn) \cup (\frac{3 π}{2} + 2 πn, 2 π + 2 πn)

Range : (- 1, 1)

Solution steps

Periodicity of

\frac{tan ( x ) - sin ( x )}{1 - sec ( x )} : 2 π

Domain of

\frac{tan ( x ) - sin ( x )}{1 - sec ( x )} : 2 πn < x < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < x < \frac{3 π}{2} + 2 πn or \frac{3 π}{2} + 2 πn < x < 2 π + 2 πn

Range of

\frac{tan ( x ) - sin ( x )}{1 - sec ( x )} : - 1 < f (x) < 1

Axis interception points of

\frac{tan ( x ) - sin ( x )}{1 - sec ( x )} :

X Intercepts

: (π + 2 πn, 0)

Asymptotes of

\frac{tan ( x ) - sin ( x )}{1 - sec ( x )} :

None

Extreme Points of

\frac{tan ( x ) - sin ( x )}{1 - sec ( x )} :

None

r, r = 1 + 3 cos (θ)

f (x) = lo g_{10} (cos (x))

y = x^{3} + 1

f (x) = \frac{1}{4} x^{4} - \frac{2}{3} x^{3} - \frac{1}{2} x^{2} + 2 x - 1

What is the f(x)=(tan(x)-sin(x))/(1-sec(x)) ?
The f(x)=(tan(x)-sin(x))/(1-sec(x)) is