What is the inverse of f(x)=x^2-4x+7 ?

The inverse of f(x)=x^2-4x+7 is 2+sqrt(x-3),2-sqrt(x-3)

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inverse of f(x)=x^2-4x+7

inverse

f (x) = x^{2} - 4 x + 7

2 + x - 3, 2 - x - 3

Solution steps

y = x^{2} - 4 x + 7

Replace

x

with

y

x = y^{2} - 4 y + 7

Solve for

y, x = y^{2} - 4 y + 7

2 + x - 3, 2 - x - 3

f (x) = 3 e^{x}

x^{2} - 8

f (x) = 4^{x + 7}

\frac{4}{x ^{2}}

- 9 x^{7} + 3 x^{5} + 2 x^{4} - x^{3} - 2 x^{2} + 4 x + 6

What is the inverse of f(x)=x^2-4x+7 ?
The inverse of f(x)=x^2-4x+7 is 2+sqrt(x-3),2-sqrt(x-3)