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Popular >

p(x)=x^3-2x-4

Solution

p (x) = x^{3} - 2 x - 4

Solution

Domain : - \infty < x < \infty

Range : - \infty < f (x) < \infty

X Intercepts : (2, 0), Y Intercepts : (0, - 4)

Asymptotes : None

Extreme Points : Maximum (- \frac{2}{3}, - (\frac{2}{3})^{\frac{3}{2}} + 2 \frac{2}{3} - 4), Minimum (\frac{2}{3}, (\frac{2}{3})^{\frac{3}{2}} - 2 \frac{2}{3} - 4)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

x^{3} - 2 x - 4 : - \infty < x < \infty

Range of

x^{3} - 2 x - 4 : - \infty < f (x) < \infty

Axis interception points of

x^{3} - 2 x - 4 :

X Intercepts

: (2, 0),

Y Intercepts

: (0, - 4)

Asymptotes of

x^{3} - 2 x - 4 :

None

Extreme Points of

x^{3} - 2 x - 4 :

Maximum

(- \frac{2}{3}, - (\frac{2}{3})^{\frac{3}{2}} + 2 \frac{2}{3} - 4),

Minimum

(\frac{2}{3}, (\frac{2}{3})^{\frac{3}{2}} - 2 \frac{2}{3} - 4)

Popular Examples

f(x)=ln((x-1)/(x+1))

f (x) = ln (\frac{x - 1}{x + 1})

f(x)=(16)/(x^2)

f (x) = \frac{16}{x ^{2}}

h(t)=-16t^2+149t+108

h (t) = - 16 t^{2} + 149 t + 108

f (n) = sin (\frac{1}{n})

f(x)=(x^2+8x+12)/(x+2)

f (x) = \frac{x ^{2} + 8 x + 12}{x + 2}

Frequently Asked Questions (FAQ)

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