What is the f(x)=(-x^2+2x+8)/(2x^2-16x+32) ?

The f(x)=(-x^2+2x+8)/(2x^2-16x+32) is

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f(x)=(-x^2+2x+8)/(2x^2-16x+32)

f (x) = \frac{- x ^{2} + 2 x + 8}{2 x ^{2} - 16 x + 32}

Domain : x < 4 or x > 4

Range : f (x) < - \frac{1}{2} or f (x) > - \frac{1}{2}

X Intercepts : (- 2, 0), Y Intercepts : (0, \frac{1}{4})

Asymptotes : Vertical x = 4, Horizontal y = - \frac{1}{2}

Extreme Points : None

Interval Notation

Domain : (- \infty, 4) \cup (4, \infty)

Range : (- \infty, - \frac{1}{2}) \cup (- \frac{1}{2}, \infty)

Solution steps

Domain of

\frac{- x ^{2} + 2 x + 8}{2 x ^{2} - 16 x + 32} : x < 4 or x > 4

Range of

\frac{- x ^{2} + 2 x + 8}{2 x ^{2} - 16 x + 32} : f (x) < - \frac{1}{2} or f (x) > - \frac{1}{2}

Axis interception points of

\frac{- x ^{2} + 2 x + 8}{2 x ^{2} - 16 x + 32} :

X Intercepts

: (- 2, 0),

Y Intercepts

: (0, \frac{1}{4})

Asymptotes of

\frac{- x ^{2} + 2 x + 8}{2 x ^{2} - 16 x + 32} :

Vertical

: x = 4,

Horizontal

: y = - \frac{1}{2}

Extreme Points of

\frac{- x ^{2} + 2 x + 8}{2 x ^{2} - 16 x + 32} :

None

f (x) = \frac{8}{x - 5}

y = \frac{4}{5} x + 1

y = - 8 x + 10

f (x) = \frac{5 x + 25}{2 x + 7}

f (x) = x^{3} - 3 x^{2} + 3 x - 3

What is the f(x)=(-x^2+2x+8)/(2x^2-16x+32) ?
The f(x)=(-x^2+2x+8)/(2x^2-16x+32) is