What is the f(x)=(-3x^2-18x-15)/(2x^2+9x-5) ?

The f(x)=(-3x^2-18x-15)/(2x^2+9x-5) is

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f(x)=(-3x^2-18x-15)/(2x^2+9x-5)

f (x) = \frac{- 3 x ^{2} - 18 x - 15}{2 x ^{2} + 9 x - 5}

Domain : x < - 5 or - 5 < x < \frac{1}{2} or x > \frac{1}{2}

Range : f (x) < - \frac{3}{2} or - \frac{3}{2} < f (x) < - \frac{12}{11} or f (x) > - \frac{12}{11}

X Intercepts : (- 1, 0), Y Intercepts : (0, 3)

Asymptotes : Vertical x = \frac{1}{2}, Horizontal y = - \frac{3}{2}

Extreme Points : None

Interval Notation

Domain : (- \infty, - 5) \cup (- 5, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Range : (- \infty, - \frac{3}{2}) \cup (- \frac{3}{2}, - \frac{12}{11}) \cup (- \frac{12}{11}, \infty)

Solution steps

Domain of

\frac{- 3 x ^{2} - 18 x - 15}{2 x ^{2} + 9 x - 5} : x < - 5 or - 5 < x < \frac{1}{2} or x > \frac{1}{2}

Range of

\frac{- 3 x ^{2} - 18 x - 15}{2 x ^{2} + 9 x - 5} : f (x) < - \frac{3}{2} or - \frac{3}{2} < f (x) < - \frac{12}{11} or f (x) > - \frac{12}{11}

Axis interception points of

\frac{- 3 x ^{2} - 18 x - 15}{2 x ^{2} + 9 x - 5} :

X Intercepts

: (- 1, 0),

Y Intercepts

: (0, 3)

Asymptotes of

\frac{- 3 x ^{2} - 18 x - 15}{2 x ^{2} + 9 x - 5} :

Vertical

: x = \frac{1}{2},

Horizontal

: y = - \frac{3}{2}

Extreme Points of

\frac{- 3 x ^{2} - 18 x - 15}{2 x ^{2} + 9 x - 5} :

None

f (x) = lo g_{x + 2} (2 x + 3)

y = (\frac{2}{3})^{x} + 2

f (x) = \frac{3 x ^{2} - 12 x}{x ^{2} - 2 x - 3}

f (x) = x^{3} - 12 x^{2} + 45 x + 8

f (l) = l^{2}

What is the f(x)=(-3x^2-18x-15)/(2x^2+9x-5) ?
The f(x)=(-3x^2-18x-15)/(2x^2+9x-5) is