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Popular >

f(x)=x^2+4x+5,-4<x<= 1

Solution

f (x) = x^{2} + 4 x + 5, - 4 < x \leq 1

Solution

Domain : - 4 < x \leq 1

Range : 1 \leq f (x) \leq 10

Y Intercepts : (0, 5)

Vertex : Minimum (- 2, 1)

Inverse : - 2 + x - 1, - x - 1 - 2

+1

Interval Notation

Domain : (- 4, 1]

Range : [1, 10]

Solution steps

Domain of

x^{2} + 4 x + 5, - 4 < x \leq 1 : - 4 < x \leq 1

Range of

x^{2} + 4 x + 5, - 4 < x \leq 1 : 1 \leq f (x) \leq 10

Axis interception points of

x^{2} + 4 x + 5, - 4 < x \leq 1 :

Y Intercepts

: (0, 5)

Vertex of

x^{2} + 4 x + 5, - 4 < x \leq 1 :

Minimum

(- 2, 1)

Inverse of

x^{2} + 4 x + 5, - 4 < x \leq 1 : - 2 + x - 1, - x - 1 - 2

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f(x)=(2x-5)/(x(x-3))

f (x) = \frac{2 x - 5}{x ( x - 3 )}

Frequently Asked Questions (FAQ)

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