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Popular >

f(x)= 1/(x^2-2x-3)

Solution

f (x) = \frac{1}{x ^{2} - 2 x - 3}

Solution

Domain : x < - 1 or - 1 < x < 3 or x > 3

Range : f (x) \leq - \frac{1}{4} or f (x) > 0

Y Intercepts : (0, - \frac{1}{3})

Asymptotes : Vertical x = - 1, x = 3, Horizontal y = 0

Extreme Points : Maximum (1, - \frac{1}{4})

+1

Interval Notation

Domain : (- \infty, - 1) \cup (- 1, 3) \cup (3, \infty)

Range : (- \infty, - \frac{1}{4}] \cup (0, \infty)

Solution steps

Domain of

\frac{1}{x ^{2} - 2 x - 3} : x < - 1 or - 1 < x < 3 or x > 3

Range of

\frac{1}{x ^{2} - 2 x - 3} : f (x) \leq - \frac{1}{4} or f (x) > 0

Axis interception points of

\frac{1}{x ^{2} - 2 x - 3} :

Y Intercepts

: (0, - \frac{1}{3})

Asymptotes of

\frac{1}{x ^{2} - 2 x - 3} :

Vertical

: x = - 1, x = 3,

Horizontal

: y = 0

Extreme Points of

\frac{1}{x ^{2} - 2 x - 3} :

Maximum

(1, - \frac{1}{4})

Popular Examples

f (x) = 5 x^{3} - 4

f(x)= 1/(x^2-2x+1)

f (x) = \frac{1}{x ^{2} - 2 x + 1}

f(x)=-2(x+4)^2+3

f (x) = - 2 (x + 4)^{2} + 3

y = 5 x + 14

y = - 2 + x

Frequently Asked Questions (FAQ)

What is the f(x)= 1/(x^2-2x-3) ?
The f(x)= 1/(x^2-2x-3) is