What is the critical 2y^3-3y^2-12y+6 ?

The critical 2y^3-3y^2-12y+6 is y=-1,y=2

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critical 2y^3-3y^2-12y+6

critical points

2 y^{3} - 3 y^{2} - 12 y + 6

y = - 1, y = 2

Solution steps

2 y^{3} - 3 y^{2} - 12 y + 6

Find where

f^{'} (y)

is equal to zero or undefined

y = - 1, y = 2

Identify critical points not in

f (y)

domain

Domain of

2 y^{3} - 3 y^{2} - 12 y + 6 : - \infty < y < \infty

All critical points are in domain

y = - 1, y = 2

f (x) = x^{2} - 2 x

arcsin (x)

\frac{2}{2 x + 8}

8 x + 4 y = 2

lo g_{2} (x + 1)