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Popular >

h(t)=-16t^2+32t+128

Solution

h (t) = - 16 t^{2} + 32 t + 128

Solution

Domain : - \infty < t < \infty

Range : f (t) \leq 144

X Intercepts : (- 2, 0), (4, 0), Y Intercepts : (0, 128)

Vertex : Maximum (1, 144)

Inverse : - \frac{- 4 + - t + 144}{4}, \frac{- t + 144 + 4}{4}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, 144]

Solution steps

Domain of

- 16 t^{2} + 32 t + 128 : - \infty < t < \infty

Range of

- 16 t^{2} + 32 t + 128 : f (t) \leq 144

Axis interception points of

- 16 t^{2} + 32 t + 128 :

X Intercepts

: (- 2, 0), (4, 0),

Y Intercepts

: (0, 128)

Vertex of

- 16 t^{2} + 32 t + 128 :

Maximum

(1, 144)

Inverse of

- 16 t^{2} + 32 t + 128 : - \frac{- 4 + - t + 144}{4}, \frac{- t + 144 + 4}{4}

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Frequently Asked Questions (FAQ)

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