What is the asymptotes of f(x)=(x^2-1)/(4x-4) ?

The asymptotes of f(x)=(x^2-1)/(4x-4) is Slant: y= 1/4 x+1/4

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asymptotes of f(x)=(x^2-1)/(4x-4)

asymptotes

f (x) = \frac{x ^{2} - 1}{4 x - 4}

Slant : y = \frac{1}{4} x + \frac{1}{4}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 1}{4 x - 4} :

None

Horizontal Asymptotes of

\frac{x ^{2} - 1}{4 x - 4} :

None

Slant Asymptotes of

\frac{x ^{2} - 1}{4 x - 4} : y = \frac{1}{4} x + \frac{1}{4}

Slant : y = \frac{1}{4} x + \frac{1}{4}

f (x) = \frac{1}{4} x^{2} + 2 x + 6

f (x) = ln (9 - t^{2})

y = \frac{- 7}{1 x - 3}

f (x) = \frac{60}{x ( x + 4 )}

\frac{5 ^{x}}{5 ^{x} + 3 ^{x}}

What is the asymptotes of f(x)=(x^2-1)/(4x-4) ?
The asymptotes of f(x)=(x^2-1)/(4x-4) is Slant: y= 1/4 x+1/4